Soit f(x)=x+1x−1f(x) = \dfrac{x+1}{x-1}f(x)=x−1x+1. La derivee f′(x)f'(x)f′(x) est :
f′(x)=1f'(x) = 1f′(x)=1
f′(x)=2(x−1)2f'(x) = \dfrac{2}{(x-1)^2}f′(x)=(x−1)22
f′(x)=−2(x−1)2f'(x) = \dfrac{-2}{(x-1)^2}f′(x)=(x−1)2−2
f′(x)=2x(x−1)2f'(x) = \dfrac{2x}{(x-1)^2}f′(x)=(x−1)22x
Score: 0/0